but like stinker said its pretty simple, if your good a math i can explain more laer i have class :td:
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Originally Posted by 2500HeavyDuty
(Post 533899)
who uses U cmon now lol
E (electromotive force also knows as V) I (stand for current or amperage) R (Resistance) P (power or watts) E = IR or R = E/I or I = E/R and for Power there is P = IE or P = (E^2)/R or P = (I^2)R |
:lol:
guess, it is the damn euro thing inside me... Damn, when I would get my hands on an orion amp today- real good old skool not those skinny, flimsy ones. |
Originally Posted by Jazz
(Post 533904)
What the..... I damn near deleted that as spam:s: lol
:lol88: |
Originally Posted by Deezel Stink3r
(Post 533926)
:lol:
guess, it is the damn euro thing inside me... Damn, when I would get my hands on an orion amp today- real good old skool not those skinny, flimsy ones. i kinda forget hot to set up an am with just using a DMM though :humm: |
You need:
a) Test tone cd (shoot me a pm if you need it) b) DMM with AC Voltage setting c) formula: voltage= SQRT (P x R) - use a 50Hz or 60 Hz tone ( DMM must be calibrated to this) - max RMS PWR of the amp multiplied with the speakers resistor and take the root of the result. The result is the max. voltage at peak power. turn up gain until you reach peak voltage as calculated. Or a bit lower to have a safety margin. you are done.:c: |
so is P is E^2/R
and then you have E^2/R times R which then makes E^2 and the SQRT of that is E and your measuring AC in volts so E=E :s: |
Originally Posted by Deezel Stink3r
(Post 534215)
You need:
a) Test tone cd (shoot me a pm if you need it) b) DMM with AC Voltage setting c) formula: voltage= SQRT (P x R) - use a 50Hz or 60 Hz tone ( DMM must be calibrated to this) - max RMS PWR of the amp multiplied with the speakers resistor and take the root of the result. The result is the max. voltage at peak power. turn up gain until you reach peak voltage as calculated. Or a bit lower to have a safety margin. you are done.:c:
Originally Posted by 2500HeavyDuty
(Post 534231)
so is P is E^2/R
and then you have E^2/R times R which then makes E^2 and the SQRT of that is E and your measuring AC in volts so E=E :s: hehe that was fun. anyhoo for the other guys who arent crazy at math if you have 300 watts of power (RMS) at 2 ohms comming from your amp and your subs are wired up at 2ohms resistance then V = SQRT(300watts X 2 ohms) so you get V= SQRT ( 600) so your voltage should be 24.5V :tu: |
you confused me badly...
:dang: next time I choose the formula for AC, not DC and then we go wild with complex Z, j and i |
ooh so we get to talk about magna flux and impedance now do we?:pca1:
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